To analyze the properties of a standing wave.
Procedure
Tie one end of a string to an oscillator and for the first case tie a 200g mass to the other end, and in another case tie a 150g mass. Adjust the frequency of the oscillations until standing waves are identified.
Data
CASE 1:
Harmonic n | frequency +/- 1Hz | fn = nf1 +/- n1Hz | λ +/- .01m | Δx nodes +/- .005m |
1 | 24 | 24 | 3.32 | 1.66 |
2 | 48 | 48 | 1.66 | 0.83 |
3 | 72 | 72 | 1.11 | 0.555 |
4 | 96 | 96 | 0.83 | 0.425 |
5 | 120 | 120 | 0.66 | 0.33 |
6 | 144 | 144 | 0.55 | 0.275 |
7 | 169 | 168 | 0.465 | 0.233 |
8 | 193 | 192 | 0.405 | 0.203 |
9 | 217 | 216 | 0.365 | 0.183 |
10 | 241 | 240 | 0.33 | 0.165 |
CASE 2:
Harmonic n | frequency +/- 1Hz | fn = nf1 +/- n1Hz | λ +/- .01m | Δx nodes +/- .005m |
1 | 12 | 12 | 3.32 | 1.66 |
2 | 24 | 24 | 1.66 | 0.83 |
3 | 36 | 36 | 1.11 | 0.555 |
4 | 48 | 38 | 0.83 | 0.415 |
5 | 60 | 60 | 0.663 | 0.332 |
6 | 72 | 72 | 0.543 | 0.272 |
7 | 84 | 84 | 0.475 | 0.238 |
8 | 96 | 96 | 0.412 | 0.206 |
9 | 109 | 108 | 0.369 | 0.185 |
10 | 121 | 120 | 0.334 | 0.167 |
Plotting frequency vs 1/λ :

Conclusion
There is a linear growth between the frequency and wavelength which affirms that they are inversely proportional. This relationship is given by v=fλ, where v is the slope of graph.
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