We first measure the diameter of the drilled hole which was .005m. We fill the black bucket with water up to a height of 0.066m or 3 inches. From there, we let 200 ml of water flow out and while that is happening we are measuring the time for that to happen.
| 1 | 2 | 3 | 4 | 5 | 6 | |
| t.actual | 12.04 | 11.58 | 11.26 | 11.54 | 11.19 | 10.81 |
ave. time = 11.4s
data:
Volume emptied = 2*10^-4m^3
Area of drain hole = 1.96*10^-5m^2
Height of water = .066m
With Bernoulli's equation we calculate for the theoretical time.
t.theoretical = V/(A(2gh)^(1/2))
t.theoretical = 8.98s
error analysis:
U.Volume emptied =.0002+.000001
L.Volume emptied =.0002-.000001
U.diameter of drain hole =.005+.001
L.diameter of drain hole =.005-.001
U.Area of drain hole = .0000283
L.Area of drain hole = .0000126
U.Height of water = .066+.001
L.Height of water = .066-.001
U.theoretical = 14.13s
L.theoretical = 6.13s
Our attained value was well within the error bounds. This error may be due to the fact that we considered a simple model where the height of the water was held constant which is in fact not true!
If the diameter of the hole was not measured accurately we can arrange our equation to solve for diameter with our average time value.
d = 2*(V/((pi*t(2gh)^(1/2)))^(1/2)
d = .015m
The percent error can be simple calculated as follows:
d.actual = .005
d.theoretical = .015
(d.actual-d.theoretical)/d.theoretical*100
= 66.67%
Our error is concerning, but by the nature of this experiment some error could not be avoided
No comments:
Post a Comment